Question Number 162845 by mkam last updated on 01/Jan/22
Commented by mkam last updated on 01/Jan/22
$${prove}\:{this} \\ $$
Answered by abdullahhhhh last updated on 01/Jan/22
$$\boldsymbol{\mathrm{y}}=\boldsymbol{\mathrm{x}}+\frac{\mathrm{1}}{\boldsymbol{\mathrm{y}}} \\ $$$$\boldsymbol{\mathrm{y}}^{\mathrm{2}} =\boldsymbol{\mathrm{xy}}+\mathrm{1} \\ $$$$\mathrm{2}\boldsymbol{\mathrm{y}}\frac{\boldsymbol{\mathrm{dy}}}{\boldsymbol{\mathrm{dx}}}\:=\:\boldsymbol{\mathrm{x}}\frac{\boldsymbol{\mathrm{dy}}}{\boldsymbol{\mathrm{dx}}}+\boldsymbol{\mathrm{y}} \\ $$$$\frac{\boldsymbol{\mathrm{dy}}}{\boldsymbol{\mathrm{dx}}}=\frac{\boldsymbol{\mathrm{y}}}{\mathrm{2}\boldsymbol{\mathrm{y}}−\boldsymbol{\mathrm{x}}} \\ $$
Commented by peter frank last updated on 02/Jan/22
$$\mathrm{great} \\ $$