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Question-163226




Question Number 163226 by nurtani last updated on 05/Jan/22
Commented by Rasheed.Sindhi last updated on 06/Jan/22
Sir mr W,why have you deleted your  answer?
SirmrW,whyhaveyoudeletedyouranswer?
Commented by mr W last updated on 06/Jan/22
sometimes i delete my answer when  i see that there exists already the   same or similar answer from other  people.
sometimesideletemyanswerwheniseethatthereexistsalreadythesameorsimilaranswerfromotherpeople.
Commented by Rasheed.Sindhi last updated on 06/Jan/22
Understood sir!
Understoodsir!
Answered by cortano1 last updated on 05/Jan/22
  2^(5x−1)  . 3^(4x+1)  .7^(3x+3)  = 2^(3x−6)  .3^(2x−4)  .7^(x−2)    ⇒x=−(5/2)
25x1.34x+1.73x+3=23x6.32x4.7x2x=52
Answered by Rasheed.Sindhi last updated on 05/Jan/22
2^(5x−1) .3^(4x+1) .7^(3x+3) =(2^3 .3^2 .7)^(x−2)          =2^(3x−6) .3^(2x−4) .7^(x−2))   2^(5x−1−3x+6) .3^(4x+1−2x+4) .7^(3x+3−x+2) =1  2^(2x+5) .3^(2x+5) .7^(2x+5) =1  (2.3.7)^(2x+5) =(2.3.7)^0   2x+5=0  x=−(5/2)
25x1.34x+1.73x+3=(23.32.7)x2=23x6.32x4.7x2)25x13x+6.34x+12x+4.73x+3x+2=122x+5.32x+5.72x+5=1(2.3.7)2x+5=(2.3.7)02x+5=0x=52

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