Question Number 163856 by mathlove last updated on 11/Jan/22
Answered by bobhans last updated on 11/Jan/22
$$\:\frac{\mathrm{49}}{\mathrm{15}}\:=\:\mathrm{3}+\frac{\mathrm{4}}{\mathrm{15}}\:=\:\mathrm{3}+\frac{\mathrm{1}}{\left(\frac{\mathrm{15}}{\mathrm{4}}\right)}\:=\:\mathrm{3}+\frac{\mathrm{1}}{\mathrm{3}+\frac{\mathrm{3}}{\mathrm{4}}}\:=\:\mathrm{3}+\frac{\mathrm{1}}{\mathrm{3}+\frac{\mathrm{1}}{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{3}}}} \\ $$$$\:\mathrm{x}=\mathrm{3},\:\mathrm{y}=\mathrm{1}\:,\:\mathrm{z}=\:\mathrm{x}=\mathrm{3}\:\rightarrow\sqrt{\mathrm{xyz}}\:=\:\mathrm{3}=\mathrm{x}=\mathrm{z} \\ $$
Commented by mathlove last updated on 11/Jan/22
$${thanks} \\ $$