Question-163978

Question Number 163978 by Eric002 last updated on 12/Jan/22

Commented by Eric002 last updated on 12/Jan/22

a c o n t i n u o u s t i m e s i g n a l s h o w n i n t h e

f i g . d e t e r m i n e t h e f o l l o w i n g v e r s i o n o f

t h e s i g n a l

a) x (t + 2)

b) - (x) t

c) x (3 - 2 t)

d) \frac{x (t) + x (- t)}{2}

Commented by JDamian last updated on 12/Jan/22

A "continuous" time signal in the popular meaning I guess, because that x(t) for t=1 is not continuous in the mathematical meaning

Commented by Eric002 last updated on 13/Jan/22

t h a n k y o u s i r f o r y o u r c o m m e n t

i n c o m m u n i c a t i o n s i g n a l s

c o u n t i n u o u s t i m e s i g n a l s

m e a n s t h e v a l u e o f (t) i s c o u n t i n u e

i n x (t) n o t d i s c r e t e p o i n t s s o c o u n t i u e

t i m e s i g n a l s n e e d n o t t o b e c o u n t i n u o u e s

m a t h m a t i c a l y

Commented by Eric002 last updated on 13/Jan/22

Commented by Eric002 last updated on 13/Jan/22

f o r e x a m p l e a i s c o u n t i n u o u s t i m e s i g n a l

a n d b i s d i s c r e t e t i m e s i g n a l

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