Question Number 164753 by akolade last updated on 21/Jan/22
Answered by som(math1967) last updated on 21/Jan/22
$${Xlog}_{\mathrm{5}} \mathrm{5}×\mathrm{12} \\ $$$$={X}\left({log}_{\mathrm{5}} \mathrm{5}+{log}_{\mathrm{5}} \mathrm{12}\right) \\ $$$$={log}_{\mathrm{12}} \mathrm{5}\left(\mathrm{1}+{log}_{\mathrm{5}} \mathrm{12}\right) \\ $$$$={log}_{\mathrm{12}} \mathrm{5}+{log}_{\mathrm{12}} \mathrm{5}×{log}_{\mathrm{5}} \mathrm{12} \\ $$$$={X}+\mathrm{1} \\ $$