Menu Close

Question-164996




Question Number 164996 by Mathematification last updated on 24/Jan/22
Answered by mr W last updated on 25/Jan/22
AB=x_1 +x_2   AB=(√((3+2)^2 −(3−2)^2 ))+(√((2+1.5)^2 −(4.5−2)^2 ))  AB=(√(24))+(√6)=3(√6)
$${AB}={x}_{\mathrm{1}} +{x}_{\mathrm{2}} \\ $$$${AB}=\sqrt{\left(\mathrm{3}+\mathrm{2}\right)^{\mathrm{2}} −\left(\mathrm{3}−\mathrm{2}\right)^{\mathrm{2}} }+\sqrt{\left(\mathrm{2}+\mathrm{1}.\mathrm{5}\right)^{\mathrm{2}} −\left(\mathrm{4}.\mathrm{5}−\mathrm{2}\right)^{\mathrm{2}} } \\ $$$${AB}=\sqrt{\mathrm{24}}+\sqrt{\mathrm{6}}=\mathrm{3}\sqrt{\mathrm{6}} \\ $$
Commented by mr W last updated on 25/Jan/22
Commented by Tawa11 last updated on 25/Jan/22
Great sir
$$\mathrm{Great}\:\mathrm{sir} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *