Question-165136

Question Number 165136 by saboorhalimi last updated on 26/Jan/22

Answered by MJS_new last updated on 26/Jan/22

obviously a = 8

\log_{3} 9 = \log_{4} 16 = 2

Commented by saboorhalimi last updated on 26/Jan/22

S o l u t i o n ?

Commented by MJS_new last updated on 26/Jan/22

no general solution method exists

Answered by mahdipoor last updated on 26/Jan/22

\Rightarrow 4^{t} - 3^{t} = a + 8 - (a + 1) = 7

\Rightarrow t = 2

4^{t} = 16 = a + 8 \Rightarrow a = 8

Answered by kapoorshah last updated on 26/Jan/22

\log_{3} 4 = \log_{(a + 1)} (a + 8)

a + 1 = 3^{2}

a + 8 = 4^{2}

a = 8

Commented by saboorhalimi last updated on 26/Jan/22

h o w c o u l d y o u c h a n g e i t i n t o t h i s

f o r m