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Question-165301




Question Number 165301 by mathdave last updated on 28/Jan/22
Answered by som(math1967) last updated on 29/Jan/22
1.No of ways ′median′ be arranged   6!=720  2. M begin   M □□□□□^5 P_5 =120  3. N end    □□□□□N  ^5 P_5 =120  4.Begin with M and end with N      M□□□□N   ^4 P_4 =24
$$\mathrm{1}.\boldsymbol{{No}}\:\boldsymbol{{of}}\:\boldsymbol{{ways}}\:'\boldsymbol{{median}}'\:\boldsymbol{{be}}\:\boldsymbol{{arranged}} \\ $$$$\:\mathrm{6}!=\mathrm{720} \\ $$$$\mathrm{2}.\:\boldsymbol{{M}}\:\boldsymbol{{begin}} \\ $$$$\:\boldsymbol{{M}}\:\Box\Box\Box\Box\Box\:^{\mathrm{5}} \boldsymbol{{P}}_{\mathrm{5}} =\mathrm{120} \\ $$$$\mathrm{3}.\:\boldsymbol{{N}}\:\boldsymbol{{end}} \\ $$$$\:\:\Box\Box\Box\Box\Box\boldsymbol{{N}}\:\:\:^{\mathrm{5}} \boldsymbol{{P}}_{\mathrm{5}} =\mathrm{120} \\ $$$$\mathrm{4}.\boldsymbol{{Begin}}\:\boldsymbol{{with}}\:\boldsymbol{{M}}\:\boldsymbol{{and}}\:\boldsymbol{{end}}\:\boldsymbol{{with}}\:\boldsymbol{{N}} \\ $$$$\:\:\:\:\boldsymbol{{M}}\Box\Box\Box\Box\boldsymbol{{N}}\:\:\:\:^{\mathrm{4}} \boldsymbol{{P}}_{\mathrm{4}} =\mathrm{24} \\ $$

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