Question-165514

Question Number 165514 by Tawa11 last updated on 02/Feb/22

Answered by som(math1967) last updated on 03/Feb/22

a) l e t r a d i u s O C = x

∴ O D = (x - 2)

f r o m △ O E D

x^{2} = 6^{2} + {(x - 2)}^{2}

x^{2} = 36 + x^{2} - 4 x + 4 \Rightarrow x = 10

b)

∠ E O C = \sin^{- 1} \frac{6}{10} = 37^{°} ° (a p r o x)

a r e a o f s e c t o r

= \frac{37}{360} \times π \times 10^{2} s q m

Commented by som(math1967) last updated on 03/Feb/22

Commented by Tawa11 last updated on 03/Feb/22

Thanks sir . I appreciate . God bless you sir .

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