Question-16579

Question Number 16579 by Joel577 last updated on 24/Jun/17

Commented by Joel577 last updated on 24/Jun/17

Mr . Ajfour, why ∠ P is 2 θ ?

Commented by Joel577 last updated on 24/Jun/17

pls explain sir

Commented by ajfour last updated on 24/Jun/17

let point above P on CD is Q .

I have let ∠ DPQ = θ

PQ = DQ, so ∠ PDQ = ∠ DPQ = θ

∠ CQP = ∠ PDQ + ∠ DPQ = 2 θ

Now BP = radius r

Also CP = r and CQ = BP = r

hence CP = CQ

so ∠ CPQ = ∠ CQP = 2 θ .

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