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Question-166104




Question Number 166104 by oustmuchiya@gmail.com last updated on 13/Feb/22
Answered by nikif99 last updated on 13/Feb/22
A: (A_x ,A_y )=(−5,1), B: (B_x ,B_y )=(−7,−8),   C: (C_x ,C_y ), D: (D_x ,D_y )  C_x =B_x +(B_x −A_x )=−7+(−7−(−5))=−9  C_y =B_y +(B_y −A_y )=−8+(−8−1)=−17  (C_x ,C_y )=(−9,−17)  D_x =C_x +(C_x −A_x )=−9+(−9−(−5))=−13  D_y =C_y +(C_y −A_y )=−17+(−17−1)=−35  (D_x ,D_y )=(−13,−35)
$${A}:\:\left({A}_{{x}} ,{A}_{{y}} \right)=\left(−\mathrm{5},\mathrm{1}\right),\:{B}:\:\left({B}_{{x}} ,{B}_{{y}} \right)=\left(−\mathrm{7},−\mathrm{8}\right),\: \\ $$$${C}:\:\left({C}_{{x}} ,{C}_{{y}} \right),\:{D}:\:\left({D}_{{x}} ,{D}_{{y}} \right) \\ $$$${C}_{{x}} ={B}_{{x}} +\left({B}_{{x}} −{A}_{{x}} \right)=−\mathrm{7}+\left(−\mathrm{7}−\left(−\mathrm{5}\right)\right)=−\mathrm{9} \\ $$$${C}_{{y}} ={B}_{{y}} +\left({B}_{{y}} −{A}_{{y}} \right)=−\mathrm{8}+\left(−\mathrm{8}−\mathrm{1}\right)=−\mathrm{17} \\ $$$$\left({C}_{{x}} ,{C}_{{y}} \right)=\left(−\mathrm{9},−\mathrm{17}\right) \\ $$$${D}_{{x}} ={C}_{{x}} +\left({C}_{{x}} −{A}_{{x}} \right)=−\mathrm{9}+\left(−\mathrm{9}−\left(−\mathrm{5}\right)\right)=−\mathrm{13} \\ $$$${D}_{{y}} ={C}_{{y}} +\left({C}_{{y}} −{A}_{{y}} \right)=−\mathrm{17}+\left(−\mathrm{17}−\mathrm{1}\right)=−\mathrm{35} \\ $$$$\left({D}_{{x}} ,{D}_{{y}} \right)=\left(−\mathrm{13},−\mathrm{35}\right) \\ $$
Commented by nikif99 last updated on 13/Feb/22

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