Question Number 166273 by MikeH last updated on 17/Feb/22
Commented by MikeH last updated on 17/Feb/22
$$\mathrm{The}\:\mathrm{figure}\:\mathrm{above}\:\mathrm{is}\:\mathrm{a}\:\mathrm{circumcircle} \\ $$$$\mathrm{ABC}\:\mathrm{with}\:\mathrm{centre}\:\mathrm{O}\:\mathrm{and}\:\mathrm{angle}\: \\ $$$$\mathrm{AOB}\:=\:\mathrm{50}°.\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{angles} \\ $$$$\mathrm{marked}\:\mathrm{x}\:\mathrm{and}\:\mathrm{y}. \\ $$
Answered by TheSupreme last updated on 17/Feb/22
$${x}=\mathrm{50}° \\ $$$${y}=\mathrm{25}° \\ $$
Commented by MikeH last updated on 17/Feb/22
$$\mathrm{how}\:\mathrm{please}? \\ $$
Answered by nurtani last updated on 17/Feb/22
$$\measuredangle{y}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\:\measuredangle\:{AOB}\:\left({facing}\:{the}\:{same}\:{arc}\:\:{A}\overset{\frown} {{B}}\right) \\ $$