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Question-166491




Question Number 166491 by mathlove last updated on 21/Feb/22
Commented by cortano1 last updated on 21/Feb/22
  = (1/(16))x−(1/(64)) sin 4x +(1/(48)) sin^3 2x + c
$$\:\:=\:\frac{\mathrm{1}}{\mathrm{16}}\mathrm{x}−\frac{\mathrm{1}}{\mathrm{64}}\:\mathrm{sin}\:\mathrm{4x}\:+\frac{\mathrm{1}}{\mathrm{48}}\:\mathrm{sin}\:^{\mathrm{3}} \mathrm{2x}\:+\:\mathrm{c} \\ $$
Commented by mathlove last updated on 21/Feb/22
solve it?
$${solve}\:{it}? \\ $$
Commented by cortano1 last updated on 21/Feb/22
yes
$$\mathrm{yes} \\ $$
Commented by mathlove last updated on 21/Feb/22

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