Question Number 166491 by mathlove last updated on 21/Feb/22
Commented by cortano1 last updated on 21/Feb/22
$$\:\:=\:\frac{\mathrm{1}}{\mathrm{16}}\mathrm{x}−\frac{\mathrm{1}}{\mathrm{64}}\:\mathrm{sin}\:\mathrm{4x}\:+\frac{\mathrm{1}}{\mathrm{48}}\:\mathrm{sin}\:^{\mathrm{3}} \mathrm{2x}\:+\:\mathrm{c} \\ $$
Commented by mathlove last updated on 21/Feb/22
$${solve}\:{it}? \\ $$
Commented by cortano1 last updated on 21/Feb/22
$$\mathrm{yes} \\ $$
Commented by mathlove last updated on 21/Feb/22