Question-167058

Tinku Tara June 4, 2023 Coordinate Geometry 0 Comments

Question Number 167058 by cortano1 last updated on 05/Mar/22

Answered by mr W last updated on 05/Mar/22

((2/r)+(1/1)−(1/2))^2 =2((2/r^2 )+(1/1^2 )+(1/2^2 )) (1/r)=(9/8) ⇒r=(8/9)

$$\left(\frac{\mathrm{2}}{{r}}+\frac{\mathrm{1}}{\mathrm{1}}−\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} =\mathrm{2}\left(\frac{\mathrm{2}}{{r}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{1}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2}} }\right) \\ $$$$\frac{\mathrm{1}}{{r}}=\frac{\mathrm{9}}{\mathrm{8}} \\ $$$$\Rightarrow{r}=\frac{\mathrm{8}}{\mathrm{9}} \\ $$

Commented by cortano1 last updated on 05/Mar/22