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Question-167252




Question Number 167252 by mkam last updated on 10/Mar/22
Answered by mr W last updated on 11/Mar/22
(∂f/∂t)=−2x×r sin t+2x×r cos t−2y r sin t+2y×r cos t  (∂f/∂r)=2x×cos t+2x×sin t+2y cos t+2y×sin t
$$\frac{\partial{f}}{\partial{t}}=−\mathrm{2}{x}×{r}\:\mathrm{sin}\:{t}+\mathrm{2}{x}×{r}\:\mathrm{cos}\:{t}−\mathrm{2}{y}\:{r}\:\mathrm{sin}\:{t}+\mathrm{2}{y}×{r}\:\mathrm{cos}\:{t} \\ $$$$\frac{\partial{f}}{\partial{r}}=\mathrm{2}{x}×\mathrm{cos}\:{t}+\mathrm{2}{x}×\mathrm{sin}\:{t}+\mathrm{2}{y}\:\mathrm{cos}\:{t}+\mathrm{2}{y}×\mathrm{sin}\:{t} \\ $$

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