Question-167594 Tinku Tara June 4, 2023 Trigonometry 0 Comments FacebookTweetPin Question Number 167594 by infinityaction last updated on 20/Mar/22 Answered by som(math1967) last updated on 20/Mar/22 cosx+cosy+cosz=pcos(x+y+z)cosxcos(x+y+z)+cosycos(x+y+z)+coszcos(x+y+z)=pcos2(x+y+z)Missing or unrecognized delimiter for \leftMissing or unrecognized delimiter for \leftsamewaysinxsin(x+y+z)+sinysin(x+y+z)+sinzsin(x+y+z)=psin2(x+y+z)Missing or unrecognized delimiter for \leftMissing or unrecognized delimiter for \leftcasei)+caseii)cosxcos(x+y+z)+sinxsin(x+y+z)+cosycos(x+y+z)+sinysin(x+y+z)coszcos(x+y+z)+sinzsin(x+y+z)=p{sin2(x+y+z)+cos2(x+y+z)}cos(x+y+z−x)+cos(x+y+z−y)+cos(x+y+z−z)=p×1∴cos(x+y)+cos(y+z)+cos(z+x)=p Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: prove-by-useing-the-polar-cordinaite-0-a-2-y-a-2-y-2-x-dx-dy-5-a-3-24-Next Next post: 0-1-sin-logx-logx-dx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.