Question Number 168093 by leicianocosta last updated on 02/Apr/22
Answered by nurtani last updated on 03/Apr/22
$${sin}\:\mathrm{60}°\:=\:\frac{\mathrm{2}}{{d}} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{3}}\:=\:\frac{\mathrm{2}}{{d}}\: \\ $$$$\sqrt{\mathrm{3}}\:{d}\:=\:\mathrm{4}\Rightarrow\:{d}\:=\:\frac{\mathrm{4}}{\:\sqrt{\mathrm{3}}}\:\centerdot\:\frac{\sqrt{\mathrm{3}}}{\:\sqrt{\mathrm{3}}}\:=\:\frac{\mathrm{4}}{\mathrm{3}}\sqrt{\mathrm{3}}\:{m}\:\left({b}\right) \\ $$