Question Number 168274 by Mastermind last updated on 07/Apr/22
Answered by MikeH last updated on 07/Apr/22
$$\mathrm{width}\:=\:{x} \\ $$$$\mathrm{length}\:={x}\:+\:\mathrm{11} \\ $$$$\mathrm{area}\:=\:{x}\left({x}+\mathrm{11}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:=\:{x}^{\mathrm{2}} +\mathrm{11}{x} \\ $$$$\mathrm{but}\:\mathrm{area}\:=\:\mathrm{60}\:\mathrm{cm}^{\mathrm{2}} \\ $$$$\Rightarrow\:\:{x}^{\mathrm{2}} +\mathrm{11}{x}\:=\:\mathrm{60} \\ $$$$\Rightarrow\:{x}^{\mathrm{2}} +\mathrm{11}{x}−\mathrm{60}\:=\:\mathrm{0} \\ $$$$\:{x}\:=\:−\mathrm{15}\:\mathrm{cm}\:\mathrm{or}\:{x}\:=\:\mathrm{4}\:\mathrm{cm} \\ $$$$\Rightarrow\:\mathrm{width}\:=\:\mathrm{4}\:\mathrm{cm} \\ $$
Commented by otchereabdullai@gmail.com last updated on 07/Apr/22
$$\mathrm{nice} \\ $$