Question-168361

Question Number 168361 by leicianocosta last updated on 08/Apr/22

Answered by som(math1967) last updated on 09/Apr/22

x = - k z - 5

x + 5 = - k z

\frac{x + 5}{- k} = z

y = - 3 z \Rightarrow \frac{y}{- 3} = z

e q u n . o f r \frac{x + 5}{- k} = \frac{y}{- 3} = \frac{z}{1}

e q u n . o f s

\frac{x + 3}{- 1} = \frac{y - 2}{- 2} = \frac{z + 1}{1}

r a n d s p e r p e n d i c u l a r

(- k) (- 1) + (- 3) (- 2) + (1) (1) = 0

\Rightarrow k + 7 = 0 ∴ k = - 7