Question Number 168679 by Tawa11 last updated on 15/Apr/22
Answered by mr W last updated on 15/Apr/22
$${N}={total}\:{force}\:{in}\:{A}−{frame} \\ $$$${N}_{{x}} =\mathrm{450}\:\mathrm{cos}\:\mathrm{20}° \\ $$$${N}_{{y}} =\mathrm{450}\:\mathrm{sin}\:\mathrm{20}°+\mathrm{10000} \\ $$$${N}=\sqrt{\left(\mathrm{450}\:\mathrm{cos}\:\mathrm{20}°\right)^{\mathrm{2}} +\left(\mathrm{450}\:\mathrm{sin}\:\mathrm{20}°+\mathrm{10000}\right)^{\mathrm{2}} } \\ $$$$\:\:=\sqrt{\mathrm{450}^{\mathrm{2}} \:+\mathrm{10000}^{\mathrm{2}} +\mathrm{2}×\mathrm{10000}×\mathrm{450}\:\mathrm{sin}\:\mathrm{20}°} \\ $$$$\:\:\approx\mathrm{10163}\:{N} \\ $$
Commented by Tawa11 last updated on 15/Apr/22
$$\mathrm{Wow},\:\mathrm{I}\:\mathrm{really}\:\mathrm{appreciate}\:\mathrm{your}\:\mathrm{time}\:\mathrm{sir}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{more}. \\ $$
Answered by mr W last updated on 15/Apr/22
Commented by mr W last updated on 15/Apr/22
$${N}=\sqrt{\mathrm{10000}^{\mathrm{2}} +\mathrm{450}^{\mathrm{2}} −\mathrm{2}×\mathrm{1000}×\mathrm{450}×\mathrm{cos}\:\mathrm{110}°} \\ $$$$\:\:\:\approx\mathrm{10163}\:{N} \\ $$
Commented by JDamian last updated on 15/Apr/22
I think that third square is wrong. Perhaps it is a typo for 110°. Sorry, I did not type anything about question #110. It came up magically.
Commented by mr W last updated on 16/Apr/22
$${not}\:{perhaps},\:{it}\:{is}\:{a}\:{typo}!\:{should}\:{be} \\ $$$${clear}\:{to}\:{everybody}.\:{thanks}\:{for}\:{the} \\ $$$${discovering}! \\ $$