Question Number 168787 by TOTTI last updated on 17/Apr/22
Commented by Oktamboy last updated on 17/Apr/22
$${lny}={ln}\mathrm{3}×{cosx} \\ $$$$\frac{{y}'}{{y}}=−{ln}\mathrm{3}×{sinx} \\ $$$${y}'=−{ln}\mathrm{3}×{sinx}×\mathrm{3}^{{cosx}} \\ $$