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Question-168788




Question Number 168788 by TOTTI last updated on 17/Apr/22
Commented by Oktamboy last updated on 17/Apr/22
∫xcos(x)dx=∫xdsinx=  =xsinx−∫sinxdx=  =xsinx+cosx+C
$$\int{xcos}\left({x}\right){dx}=\int{xdsinx}= \\ $$$$={xsinx}−\int{sinxdx}= \\ $$$$={xsinx}+{cosx}+{C} \\ $$

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