Question Number 168830 by amin96 last updated on 18/Apr/22
Commented by mr W last updated on 22/Apr/22
$${seems}\:{wrong}! \\ $$$${PB}={PD}=\mathrm{3} \\ $$$${AB}={AP}+{PB}=\mathrm{9}+\mathrm{3}=\mathrm{12} \\ $$$$\frac{{DB}}{{DP}}=\frac{{AB}}{{DB}}\: \\ $$$$\Rightarrow{DB}=\sqrt{{DP}×{AB}}=\sqrt{\mathrm{3}×\mathrm{12}}=\mathrm{6} \\ $$$$\Rightarrow\:{impossible}! \\ $$