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Question-169105




Question Number 169105 by mr W last updated on 24/Apr/22
Commented by mr W last updated on 24/Apr/22
find MN=?
$${find}\:{MN}=? \\ $$
Answered by greougoury555 last updated on 24/Apr/22
MP×(14+NQ)=20×12  (MP+14)×NQ=24×10   { ((14MP+MP.NQ=240)),((14NQ+MP.NQ=240)) :}  ⇒MP=NQ  let MP=NQ=a  ⇒a^2 +14a−240=0  ⇒(a+24)(a−10)=0; a=10=MP=NQ  ⇒MN = 34
$${MP}×\left(\mathrm{14}+{NQ}\right)=\mathrm{20}×\mathrm{12} \\ $$$$\left({MP}+\mathrm{14}\right)×{NQ}=\mathrm{24}×\mathrm{10} \\ $$$$\begin{cases}{\mathrm{14}{MP}+{MP}.{NQ}=\mathrm{240}}\\{\mathrm{14}{NQ}+{MP}.{NQ}=\mathrm{240}}\end{cases} \\ $$$$\Rightarrow{MP}={NQ} \\ $$$${let}\:{MP}={NQ}={a} \\ $$$$\Rightarrow{a}^{\mathrm{2}} +\mathrm{14}{a}−\mathrm{240}=\mathrm{0} \\ $$$$\Rightarrow\left({a}+\mathrm{24}\right)\left({a}−\mathrm{10}\right)=\mathrm{0};\:{a}=\mathrm{10}={MP}={NQ} \\ $$$$\Rightarrow{MN}\:=\:\mathrm{34} \\ $$
Commented by mr W last updated on 24/Apr/22
thanks!
$${thanks}! \\ $$

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