Question-169281

Question Number 169281 by mnjuly1970 last updated on 28/Apr/22

Commented by cortano1 last updated on 28/Apr/22

\tan β = \frac{1}{5}, \tan (α + β) = \frac{1}{2}

\Rightarrow \tan α = \frac{3}{11}

∴ \tan (45 ° + α) . \tan (45 ° - β) =

\frac{1 + \frac{3}{11}}{1 - \frac{3}{11}} . \frac{1 - \frac{1}{5}}{1 + \frac{1}{5}} = \frac{14}{8} . \frac{2}{3} = \frac{7}{6}

Commented by mnjuly1970 last updated on 28/Apr/22

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