Question-169480

Question Number 169480 by TOTTI last updated on 01/May/22

Answered by MikeH last updated on 01/May/22

(a) \lim_{x \to 1^{-}} g (x) = \lim_{x \to 1} x = 1

(b) \lim_{x \to 1^{+}} g (x) = \lim_{x \to 1} (2 - x^{2}) = 1

∴ \lim_{x \to 1} g (x) = 1

(c) g (1) = 3

(d) \lim_{x \to 2^{-}} g (x) = \lim_{x \to 2} (2 - x^{2}) = - 2

(e) \lim_{x \to 2^{+}} g (x) = \lim_{x \to 2} (x - 3) = - 1

hence \lim_{x \to 2} g (x) does not exist .

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