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Question-169501




Question Number 169501 by Giantyusuf last updated on 01/May/22
Answered by qaz last updated on 01/May/22
lim_(n→∞) n((π/2)−arctan n)=lim_(n→∞) narctan (1/n)=1
limnn(π2arctann)=limnarctann1n=1

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