Question Number 169572 by mnjuly1970 last updated on 03/May/22
Answered by mr W last updated on 03/May/22
$${EO}={OC}=\mathrm{1},\:{say} \\ $$$$\angle{HOC}=\angle{AOE}=\angle{B} \\ $$$${AE}=\mathrm{1}×\mathrm{tan}\:{B} \\ $$$$\mathrm{tan}\:{A}=\frac{{EC}}{{AE}}=\frac{\mathrm{2}}{\mathrm{1}×\mathrm{tan}\:{B}} \\ $$$$\Rightarrow\mathrm{tan}\:{A}\:×\:\mathrm{tan}\:{B}=\mathrm{2} \\ $$
Commented by mnjuly1970 last updated on 03/May/22
$$\:\:{very}\:{nice}\:{solution}\:{sir}\:{W} \\ $$$${thanks}\:{alot} \\ $$
Commented by Tawa11 last updated on 03/May/22
$$\mathrm{Great}\:\mathrm{sir} \\ $$