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Question-170100




Question Number 170100 by mathlove last updated on 16/May/22
Commented by cortano1 last updated on 16/May/22
 y=−((√3)/2) sin x−(1/2) cos x  y=−((1/2)cos x+((√3)/2) sin x)  y=−(sin (π/6) cos x + cos (π/6) sin x)  y=−sin (x+(π/6))
$$\:{y}=−\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}\:\mathrm{sin}\:{x}−\frac{\mathrm{1}}{\mathrm{2}}\:\mathrm{cos}\:{x} \\ $$$${y}=−\left(\frac{\mathrm{1}}{\mathrm{2}}\mathrm{cos}\:{x}+\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}\:\mathrm{sin}\:{x}\right) \\ $$$${y}=−\left(\mathrm{sin}\:\frac{\pi}{\mathrm{6}}\:\mathrm{cos}\:{x}\:+\:\mathrm{cos}\:\frac{\pi}{\mathrm{6}}\:\mathrm{sin}\:{x}\right) \\ $$$${y}=−\mathrm{sin}\:\left({x}+\frac{\pi}{\mathrm{6}}\right) \\ $$

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