Question Number 170374 by cortano1 last updated on 22/May/22
Commented by mr W last updated on 22/May/22
$$\mathrm{tan}\:{x}=\frac{\mathrm{tan}\:\mathrm{40}}{\mathrm{1}+\frac{\mathrm{tan}\:\mathrm{40}}{\mathrm{tan}\:\mathrm{30}}}\:\Rightarrow{x}\approx\mathrm{18}.\mathrm{88}° \\ $$
Commented by Tawa11 last updated on 08/Oct/22
$$\mathrm{Great}\:\mathrm{sir} \\ $$