Question Number 170495 by jokjok76 last updated on 25/May/22
Answered by MikeH last updated on 25/May/22
$$\mathrm{1}.\:{y}\:=\:\mathrm{3}{x}\:+{c} \\ $$$$\mathrm{2}.\:{y}\:=\:{x}^{\mathrm{2}} \:+\:{x}\:+\:{c} \\ $$$$\mathrm{3}.\:{y}\:=\:\frac{{x}^{\mathrm{6}} }{\mathrm{6}}\:+\:{x}^{−\mathrm{3}} \:+\:\frac{\mathrm{2}}{\mathrm{5}}{x}^{\frac{\mathrm{5}}{\mathrm{2}}} \:−\mathrm{3}{x}\:+\:{c} \\ $$$$\mathrm{4}.\:\mathrm{3}\left(\frac{\mathrm{3}}{\mathrm{2}}{x}^{\mathrm{4}} −\frac{{x}^{\mathrm{2}} }{\mathrm{2}}+\mathrm{5}{x}\right)\:+\:{c} \\ $$