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Question-170843




Question Number 170843 by cortano1 last updated on 01/Jun/22
Answered by floor(10²Eta[1]) last updated on 01/Jun/22
((log(x−40))/(log(√(x+1))+1))=1⇔log(x−40)=log((√(x+1))+1)  ⇔x−40=(√(x+1))+1⇔(√(x+1))=x−41  ⇔x+1=(x−41)^2 ∧x−41≥0  ⇔x^2 −83x+41^2 −1=0∧x≥41  ⇔x=((83±(√(169)))/2)∧x≥41  ⇔x=((83+13)/2)=48=x_0   ⇒(√(x_0 +1))=(√(49))=7
log(x40)logx+1+1=1log(x40)=log(x+1+1)x40=x+1+1x+1=x41x+1=(x41)2x410x283x+4121=0x41x=83±1692x41x=83+132=48=x0x0+1=49=7

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