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Question-170980




Question Number 170980 by anas_zaidan last updated on 05/Jun/22
Answered by aleks041103 last updated on 05/Jun/22
∫_2 ^4 ∫_0 ^1 x^2 ydxdy=  =(∫_0 ^1 x^2 dx)(∫_2 ^4 ydy)=  =((1/3)−(0/3))(((4^2 −2^2 )/2))=  =(1/6)(16−4)=2
$$\underset{\mathrm{2}} {\overset{\mathrm{4}} {\int}}\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}{x}^{\mathrm{2}} {ydxdy}= \\ $$$$=\left(\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}{x}^{\mathrm{2}} {dx}\right)\left(\underset{\mathrm{2}} {\overset{\mathrm{4}} {\int}}{ydy}\right)= \\ $$$$=\left(\frac{\mathrm{1}}{\mathrm{3}}−\frac{\mathrm{0}}{\mathrm{3}}\right)\left(\frac{\mathrm{4}^{\mathrm{2}} −\mathrm{2}^{\mathrm{2}} }{\mathrm{2}}\right)= \\ $$$$=\frac{\mathrm{1}}{\mathrm{6}}\left(\mathrm{16}−\mathrm{4}\right)=\mathrm{2} \\ $$

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