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Question-171014




Question Number 171014 by Beginner last updated on 06/Jun/22
Answered by greougoury555 last updated on 06/Jun/22
 = ∫((1/7)e^(7x) +3e^(−2x) )dx  =(1/(49))e^(7x) −(3/2)e^(−2x) +c
$$\:=\:\int\left(\frac{\mathrm{1}}{\mathrm{7}}{e}^{\mathrm{7}{x}} +\mathrm{3}{e}^{−\mathrm{2}{x}} \right){dx} \\ $$$$=\frac{\mathrm{1}}{\mathrm{49}}{e}^{\mathrm{7}{x}} −\frac{\mathrm{3}}{\mathrm{2}}{e}^{−\mathrm{2}{x}} +{c}\: \\ $$

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