Question Number 171034 by mathlove last updated on 06/Jun/22
Commented by cortano1 last updated on 06/Jun/22
$$\left(\mathrm{12}\right)\sqrt{{a}+\sqrt{\mathrm{1}+\mathrm{2}}}\:=\:\mathrm{2} \\ $$$$\:\:\:\:\:\:\:\:\:\:{a}+\sqrt{\mathrm{3}}=\mathrm{4}\Rightarrow{a}=\mathrm{4}−\sqrt{\mathrm{3}} \\ $$$$\left(\mathrm{13}\right)\:\sqrt{{x}+\sqrt{\mathrm{2}+\mathrm{2}}}\:=\mathrm{2} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:{x}+\mathrm{2}=\mathrm{4}\Rightarrow{x}=\mathrm{2} \\ $$
Commented by mathlove last updated on 06/Jun/22
$${thanks} \\ $$