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Question-171255




Question Number 171255 by mnjuly1970 last updated on 11/Jun/22
Commented by mr W last updated on 11/Jun/22
S_(ΔAPB) =((AB×AP cos θ)/2)                =((AD×AP cos θ)/4)                =((AP^2 )/4)                =((8×8)/4)=16
$${S}_{\Delta{APB}} =\frac{{AB}×{AP}\:\mathrm{cos}\:\theta}{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{{AD}×{AP}\:\mathrm{cos}\:\theta}{\mathrm{4}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{{AP}^{\mathrm{2}} }{\mathrm{4}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{\mathrm{8}×\mathrm{8}}{\mathrm{4}}=\mathrm{16} \\ $$
Commented by mnjuly1970 last updated on 11/Jun/22
thx alot   Sir  W ....
$${thx}\:{alot}\:\:\:{Sir}\:\:{W}\:…. \\ $$
Answered by infinityaction last updated on 11/Jun/22
Commented by mnjuly1970 last updated on 11/Jun/22
grateful sir
$${grateful}\:{sir} \\ $$

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