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Question-172261




Question Number 172261 by Mikenice last updated on 25/Jun/22
Answered by Rasheed.Sindhi last updated on 25/Jun/22
(4(√3) +7)^(2016) (4(√3) −7)^(2016)   ={(4(√3) +7)(4(√3) −7)}^(2016)   ={(4(√3) )^2 −7^2 }^(2016)   ={16(3)−49}^(2016)   ={−1}^(2016)   =1
$$\left(\mathrm{4}\sqrt{\mathrm{3}}\:+\mathrm{7}\right)^{\mathrm{2016}} \left(\mathrm{4}\sqrt{\mathrm{3}}\:−\mathrm{7}\right)^{\mathrm{2016}} \\ $$$$=\left\{\left(\mathrm{4}\sqrt{\mathrm{3}}\:+\mathrm{7}\right)\left(\mathrm{4}\sqrt{\mathrm{3}}\:−\mathrm{7}\right)\right\}^{\mathrm{2016}} \\ $$$$=\left\{\left(\mathrm{4}\sqrt{\mathrm{3}}\:\right)^{\mathrm{2}} −\mathrm{7}^{\mathrm{2}} \right\}^{\mathrm{2016}} \\ $$$$=\left\{\mathrm{16}\left(\mathrm{3}\right)−\mathrm{49}\right\}^{\mathrm{2016}} \\ $$$$=\left\{−\mathrm{1}\right\}^{\mathrm{2016}} \\ $$$$=\mathrm{1} \\ $$

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