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Question-172468




Question Number 172468 by mathlove last updated on 27/Jun/22
Commented by mokys last updated on 28/Jun/22
= (((3!!)^(3!!)  − (3^(3!!) ))/(3^(3!)  − 3^(6!!) )) = ((3^3  − 3^3 )/(3^(3!)  − 3^(6!!) )) = 0
$$=\:\frac{\left(\mathrm{3}!!\right)^{\mathrm{3}!!} \:−\:\left(\mathrm{3}^{\mathrm{3}!!} \right)}{\mathrm{3}^{\mathrm{3}!} \:−\:\mathrm{3}^{\mathrm{6}!!} }\:=\:\frac{\mathrm{3}^{\mathrm{3}} \:−\:\mathrm{3}^{\mathrm{3}} }{\mathrm{3}^{\mathrm{3}!} \:−\:\mathrm{3}^{\mathrm{6}!!} }\:=\:\mathrm{0} \\ $$

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