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Question-172603




Question Number 172603 by Mikenice last updated on 29/Jun/22
Answered by mr W last updated on 29/Jun/22
Commented by mr W last updated on 29/Jun/22
tan θ=((100)/(30))=((10)/3)  θ=tan^(−1) ((10)/3)≈73.3°
$$\mathrm{tan}\:\theta=\frac{\mathrm{100}}{\mathrm{30}}=\frac{\mathrm{10}}{\mathrm{3}} \\ $$$$\theta=\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{10}}{\mathrm{3}}\approx\mathrm{73}.\mathrm{3}° \\ $$
Commented by Tawa11 last updated on 30/Jun/22
Great sir
$$\mathrm{Great}\:\mathrm{sir} \\ $$

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