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Question-172653

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Question Number 172653 by Mikenice last updated on 29/Jun/22
Answered by MJS_new last updated on 30/Jun/22
∫(((−1)^(1/x) )/x)dx= [t=((πi)/x) → dx=((ix^2 )/π)dt] =−∫(e^t /t)dt=−Ei (t) = =−Ei (((iπ)/x)) +C
∫(−1)1/xxdx=[t=πix→dx=ix2πdt]=−∫ettdt=−Ei(t)==−Ei(iπx)+C

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