Question Number 172740 by SANOGO last updated on 30/Jun/22
Commented by Rasheed.Sindhi last updated on 30/Jun/22
$${Could}\:{you}\:{please}\:{translate}\:{into} \\ $$$$\mathcal{E}{nglish}? \\ $$
Answered by JDamian last updated on 01/Jul/22
$$\left(\mathrm{2}\right) \\ $$$$\frac{{n}^{\mathrm{2}} −\mathrm{3}{n}+\mathrm{6}}{{n}−\mathrm{1}}=\frac{{n}^{\mathrm{2}} −{n}−\mathrm{2}{n}+\mathrm{6}}{{n}−\mathrm{1}}= \\ $$$$={n}+\frac{−\mathrm{2}{n}+\mathrm{6}}{{n}−\mathrm{1}}={n}−\mathrm{2}+\frac{\mathrm{4}}{{n}−\mathrm{1}} \\ $$$$\mid{n}−\mathrm{1}\mid\:\in\:\left\{\mathrm{1},\:\mathrm{2},\:\mathrm{4}\right\} \\ $$$${n}\in\left\{−\mathrm{3},\:−\mathrm{1},\:\mathrm{0},\:\mathrm{2},\:\mathrm{3},\:\mathrm{5}\right\} \\ $$