Question Number 172817 by Mikenice last updated on 01/Jul/22
Answered by som(math1967) last updated on 02/Jul/22
$$\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}\left(\mathrm{1}+{cos}\mathrm{8}\theta\right)}}} \\ $$$$\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\mathrm{2}{cos}\mathrm{4}\theta}} \\ $$$$\sqrt{\mathrm{2}+\sqrt{\mathrm{2}\left(\mathrm{1}+{cos}\mathrm{4}\theta\right)}} \\ $$$$\sqrt{\mathrm{2}+\mathrm{2}{cos}\mathrm{2}\theta}=\sqrt{\mathrm{2}\left(\mathrm{1}+{cos}\mathrm{2}\theta\right)}=\mathrm{2}{cos}\theta \\ $$
Answered by CElcedricjunior last updated on 02/Jul/22