Question Number 172891 by cherokeesay last updated on 02/Jul/22
Commented by mr W last updated on 03/Jul/22
$${can}\:{you}\:{please}\:{make}\:{your}\:{question} \\ $$$${clear}\:{and}\:{understandable}\:{sir}? \\ $$
Commented by cherokeesay last updated on 03/Jul/22
$$ \\ $$$$\mathrm{Yes}\:\mathrm{sir},\:\mathrm{it}\:\mathrm{is}\:\mathrm{a}\:\mathrm{matter}\:\mathrm{of}\:\mathrm{finding}\:\mathrm{the}\:\mathrm{value}\:\mathrm{off} \\ $$$${f}\left(\mathrm{x}\right)\:\mathrm{when}\:\mathrm{x}\:\mathrm{is}\:\mathrm{less}\:\mathrm{than}\:\mathrm{or}\:\mathrm{equal}\:\mathrm{to}\:\mathrm{1}. \\ $$$$\mathrm{Thans}. \\ $$
Commented by mr W last updated on 03/Jul/22
$${with}\:{x}\leqslant\mathrm{1}: \\ $$$$\mid{x}−\mathrm{1}\mid=\mathrm{1}−{x} \\ $$$$\mid{x}−\mathrm{2}\mid=\mathrm{2}−{x} \\ $$$$\Rightarrow{f}\left({x}\right)=\left(\mathrm{1}−{x}\right)−\left(\mathrm{2}−{x}\right)=−\mathrm{1} \\ $$
Commented by cherokeesay last updated on 04/Jul/22
$${thank}\:{you}\:{sir}\:! \\ $$