Question Number 172947 by Mikenice last updated on 03/Jul/22
Answered by Rasheed.Sindhi last updated on 03/Jul/22
$$\mathrm{5}^{{x}−\mathrm{2}} =\frac{\mathrm{125}^{{x}−\mathrm{1}} }{\mathrm{5}^{{x}+\mathrm{2}} } \\ $$$$\mathrm{5}^{{x}−\mathrm{2}} \centerdot\mathrm{5}^{{x}+\mathrm{2}} =\left(\mathrm{5}^{\mathrm{3}} \right)^{{x}−\mathrm{1}} \\ $$$$\mathrm{5}^{\mathrm{2}{x}} =\mathrm{5}^{\mathrm{3}{x}−\mathrm{3}} \\ $$$$\mathrm{3}{x}−\mathrm{3}=\mathrm{2}{x} \\ $$$${x}=\mathrm{3} \\ $$