Question Number 173000 by Mikenice last updated on 04/Jul/22
Commented by MJS_new last updated on 04/Jul/22
$$\mathrm{2}^{{x}+{y}} =\mathrm{6}\:\Rightarrow\:{x}+{y}=\frac{\mathrm{ln}\:\mathrm{6}}{\mathrm{ln}\:\mathrm{2}}={a} \\ $$$$\mathrm{3}^{{x}+{y}} =\mathrm{4}\:\Rightarrow\:{x}+{y}=\frac{\mathrm{ln}\:\mathrm{4}}{\mathrm{ln}\:\mathrm{3}}={b} \\ $$$${a}\neq{b}\:\Rightarrow\:\mathrm{no}\:\mathrm{solution} \\ $$