Menu Close

Question-173008




Question Number 173008 by Mikenice last updated on 04/Jul/22
Answered by pnuvu last updated on 04/Jul/22
((4(x^2 −y^2 ))/(x−y))=((4(x+y)(x−y))/(x−y))=4(x+y)
$$\frac{\mathrm{4}\left({x}^{\mathrm{2}} −{y}^{\mathrm{2}} \right)}{{x}−{y}}=\frac{\mathrm{4}\left({x}+{y}\right)\left({x}−{y}\right)}{{x}−{y}}=\mathrm{4}\left({x}+{y}\right) \\ $$
Answered by Skabetix last updated on 05/Jul/22
((4x^2 −4y^2 )/(x−y))=((4(x−y)(x+y))/(x−y))=4(x+y)
$$\frac{\mathrm{4}{x}^{\mathrm{2}} −\mathrm{4}{y}^{\mathrm{2}} }{{x}−{y}}=\frac{\mathrm{4}\left({x}−{y}\right)\left({x}+{y}\right)}{{x}−{y}}=\mathrm{4}\left({x}+{y}\right) \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *