Question Number 173123 by dragan91 last updated on 06/Jul/22
Commented by MJS_new last updated on 06/Jul/22
$$\mathrm{both}\:\mathrm{are}\:\mathrm{linear}\:\mathrm{for}\:{y} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{solve}\:\mathrm{to}\:\begin{cases}{{y}=\mathrm{term}\:\mathrm{A}}\\{{y}=\mathrm{term}\:\mathrm{B}}\end{cases} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{term}\:\mathrm{A}\:=\mathrm{term}\:\mathrm{B}\:\left(\mathrm{which}\:\mathrm{is}\:\mathrm{a}\:\mathrm{polynome}\right. \\ $$$$\:\:\:\:\:\mathrm{of}\:\mathrm{4}^{\mathrm{th}} \:\mathrm{degree} \\ $$