Menu Close

Question-173380




Question Number 173380 by cortano1 last updated on 10/Jul/22
Commented by kaivan.ahmadi last updated on 10/Jul/22
∼lim_(x→0)   ((e^x −e^(−x) +2sinx)/1)=0
$$\sim{li}\underset{{x}\rightarrow\mathrm{0}} {{m}}\:\:\frac{{e}^{{x}} −{e}^{−{x}} +\mathrm{2}{sinx}}{\mathrm{1}}=\mathrm{0} \\ $$$$ \\ $$
Answered by CElcedricjunior last updated on 12/Jul/22
lim_(x→0) (( e^x −1+e^(−x) −1−2(cosx−1))/x)        =0      ....le ce^� le^� bre ce^� dric junior.......
$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{\:\boldsymbol{\mathrm{e}}^{\boldsymbol{\mathrm{x}}} −\mathrm{1}+\boldsymbol{\mathrm{e}}^{−\boldsymbol{\mathrm{x}}} −\mathrm{1}−\mathrm{2}\left(\boldsymbol{\mathrm{cosx}}−\mathrm{1}\right)}{\boldsymbol{\mathrm{x}}} \\ $$$$\:\:\:\:\:\:=\mathrm{0} \\ $$$$\: \\ $$$$\:….{le}\:{c}\acute {{e}l}\grave {{e}bre}\:{c}\acute {{e}dric}\:{junior}……. \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *