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Question-173383




Question Number 173383 by AgniMath last updated on 10/Jul/22
Answered by som(math1967) last updated on 10/Jul/22
(1/(1+a+(2/b))) +((ac)/(ac+((abc)/2)+ac.c^(−1) ))    +(a/(a+a.a^(−1) +ac))  =(1/(1+a+ac)) +((ac)/(ac+1+a)) +(a/(a+1+ac)) ★  =((1+a+ac)/(1+a+ac))=1  ★ abc=2⇒ac=(2/b), ((abc)/2)=1
$$\frac{\mathrm{1}}{\mathrm{1}+{a}+\frac{\mathrm{2}}{{b}}}\:+\frac{{ac}}{{ac}+\frac{{abc}}{\mathrm{2}}+{ac}.{c}^{−\mathrm{1}} } \\ $$$$\:\:+\frac{{a}}{{a}+{a}.{a}^{−\mathrm{1}} +{ac}} \\ $$$$=\frac{\mathrm{1}}{\mathrm{1}+{a}+{ac}}\:+\frac{{ac}}{{ac}+\mathrm{1}+{a}}\:+\frac{{a}}{{a}+\mathrm{1}+{ac}}\:\bigstar \\ $$$$=\frac{\mathrm{1}+{a}+{ac}}{\mathrm{1}+{a}+{ac}}=\mathrm{1} \\ $$$$\bigstar\:{abc}=\mathrm{2}\Rightarrow\boldsymbol{{ac}}=\frac{\mathrm{2}}{\boldsymbol{{b}}},\:\frac{\boldsymbol{{abc}}}{\mathrm{2}}=\mathrm{1} \\ $$

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