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Question-173430




Question Number 173430 by dragan91 last updated on 11/Jul/22
Commented by Rasheed.Sindhi last updated on 11/Jul/22
a=0, b=c=2  a=−1,(b,c)=(0,1),(1,0),(1,1)
$${a}=\mathrm{0},\:{b}={c}=\mathrm{2} \\ $$$${a}=−\mathrm{1},\left({b},{c}\right)=\left(\mathrm{0},\mathrm{1}\right),\left(\mathrm{1},\mathrm{0}\right),\left(\mathrm{1},\mathrm{1}\right) \\ $$
Commented by dragan91 last updated on 13/Jul/22
what about a=2 (b,c)=(2,4),(4,2)
$$\mathrm{what}\:\mathrm{about}\:\mathrm{a}=\mathrm{2}\:\left(\mathrm{b},\mathrm{c}\right)=\left(\mathrm{2},\mathrm{4}\right),\left(\mathrm{4},\mathrm{2}\right) \\ $$
Commented by Rasheed.Sindhi last updated on 13/Jul/22
These are only some solutions.Not  a perfect solution.
$$\mathcal{T}{hese}\:{are}\:{only}\:{some}\:{solutions}.{Not} \\ $$$${a}\:{perfect}\:{solution}. \\ $$

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